Base | Representation |
---|---|
bin | 11101001010100100000001… |
… | …11101110011100111011011 |
3 | 22102002012122121121112002211 |
4 | 32211102000331303213123 |
5 | 31401240143012142343 |
6 | 344223011402335551 |
7 | 16336400361512152 |
oct | 1645220075634733 |
9 | 272065577545084 |
10 | 64134615349723 |
11 | 19487379419416 |
12 | 7239874aba5b7 |
13 | 29a2b397b15c9 |
14 | 11ba1bc0b6599 |
15 | 76344db9779d |
hex | 3a5480f739db |
64134615349723 has 2 divisors, whose sum is σ = 64134615349724. Its totient is φ = 64134615349722.
The previous prime is 64134615349709. The next prime is 64134615349789. The reversal of 64134615349723 is 32794351643146.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 64134615349723 - 241 = 61935592094171 is a prime.
It is a super-2 number, since 2×641346153497232 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (64134615349223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32067307674861 + 32067307674862.
It is an arithmetic number, because the mean of its divisors is an integer number (32067307674862).
Almost surely, 264134615349723 is an apocalyptic number.
64134615349723 is a deficient number, since it is larger than the sum of its proper divisors (1).
64134615349723 is an equidigital number, since it uses as much as digits as its factorization.
64134615349723 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 39191040, while the sum is 58.
The spelling of 64134615349723 in words is "sixty-four trillion, one hundred thirty-four billion, six hundred fifteen million, three hundred forty-nine thousand, seven hundred twenty-three".
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