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64140251403 = 32931310392267
BaseRepresentation
bin111011101111000011…
…101001000100001011
320010120001012100221210
4323233003221010023
52022324401021103
645244324104203
74430312066334
oct735703510413
9203501170853
1064140251403
1125224555238
1210520535063
1360824464a7
1431666b528b
151a05e7de03
hexeef0e910b

64140251403 has 32 divisors (see below), whose sum is σ = 88876569600. Its totient is φ = 41096030976.

The previous prime is 64140251401. The next prime is 64140251411. The reversal of 64140251403 is 30415204146.

It is not a de Polignac number, because 64140251403 - 21 = 64140251401 is a prime.

It is a super-2 number, since 2×641402514032 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (64140251401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28291876 + ... + 28294142.

It is an arithmetic number, because the mean of its divisors is an integer number (2777392800).

Almost surely, 264140251403 is an apocalyptic number.

64140251403 is a deficient number, since it is larger than the sum of its proper divisors (24736318197).

64140251403 is a wasteful number, since it uses less digits than its factorization.

64140251403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3651.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 64140251403 its reverse (30415204146), we get a palindrome (94555455549).

The spelling of 64140251403 in words is "sixty-four billion, one hundred forty million, two hundred fifty-one thousand, four hundred three".

Divisors: 1 3 29 87 313 939 1039 2267 3117 6801 9077 27231 30131 65743 90393 197229 325207 709571 975621 2128713 2355413 7066239 9431003 20577559 28293009 61732677 68306977 204920931 737244269 2211732807 21380083801 64140251403