Base | Representation |
---|---|
bin | 101110101111111110001… |
… | …1100000001000000000000 |
3 | 211202020121000122011122020 |
4 | 1131133330130001000000 |
5 | 1320232313043410310 |
6 | 21355411253041440 |
7 | 1232130504005013 |
oct | 135377434010000 |
9 | 24666530564566 |
10 | 6425211310080 |
11 | 2057a0a309202 |
12 | 8792ba326280 |
13 | 377b82c1b8a4 |
14 | 182da642337a |
15 | b2203d94170 |
hex | 5d7fc701000 |
6425211310080 has 624 divisors, whose sum is σ = 21877553424384. Its totient is φ = 1609724067840.
The previous prime is 6425211310079. The next prime is 6425211310159. The reversal of 6425211310080 is 800131125246.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2816838540 + ... + 2816840820.
Almost surely, 26425211310080 is an apocalyptic number.
6425211310080 is a gapful number since it is divisible by the number (60) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 6425211310080, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (10938776712192).
6425211310080 is an abundant number, since it is smaller than the sum of its proper divisors (15452342114304).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6425211310080 is a wasteful number, since it uses less digits than its factorization.
6425211310080 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2478 (or 2437 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 33.
The spelling of 6425211310080 in words is "six trillion, four hundred twenty-five billion, two hundred eleven million, three hundred ten thousand, eighty".
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