Base | Representation |
---|---|
bin | 10010101110010000111… |
… | …00111011010001110111 |
3 | 2021111111121012012200101 |
4 | 21113020130323101313 |
5 | 41020001131400033 |
6 | 1211311201254531 |
7 | 64322620402303 |
oct | 11271034732167 |
9 | 2244447165611 |
10 | 643313153143 |
11 | 22891155a631 |
12 | a4818334447 |
13 | 48883248bcb |
14 | 231ca892d03 |
15 | 11b0265497d |
hex | 95c873b477 |
643313153143 has 4 divisors (see below), whose sum is σ = 647259859768. Its totient is φ = 639366446520.
The previous prime is 643313153137. The next prime is 643313153167. The reversal of 643313153143 is 341351313346.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341351313346 = 2 ⋅170675656673.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-643313153143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (643313153183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1973353068 + ... + 1973353393.
It is an arithmetic number, because the mean of its divisors is an integer number (161814964942).
Almost surely, 2643313153143 is an apocalyptic number.
643313153143 is a deficient number, since it is larger than the sum of its proper divisors (3946706625).
643313153143 is a wasteful number, since it uses less digits than its factorization.
643313153143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3946706624.
The product of its digits is 116640, while the sum is 37.
Adding to 643313153143 its reverse (341351313346), we get a palindrome (984664466489).
The spelling of 643313153143 in words is "six hundred forty-three billion, three hundred thirteen million, one hundred fifty-three thousand, one hundred forty-three".
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