Base | Representation |
---|---|
bin | 111011111010100110… |
… | …101010110100011001 |
3 | 20011001112201221202011 |
4 | 323322212222310121 |
5 | 2023223444424001 |
6 | 45315444305521 |
7 | 4435153555441 |
oct | 737246526431 |
9 | 204045657664 |
10 | 64333983001 |
11 | 253139466a2 |
12 | 105753a22a1 |
13 | 60b3617582 |
14 | 3184305121 |
15 | 1a17e9ad51 |
hex | efa9aad19 |
64333983001 has 2 divisors, whose sum is σ = 64333983002. Its totient is φ = 64333983000.
The previous prime is 64333982987. The next prime is 64333983011. The reversal of 64333983001 is 10038933346.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36794912400 + 27539070601 = 191820^2 + 165949^2 .
It is a cyclic number.
It is not a de Polignac number, because 64333983001 - 223 = 64325594393 is a prime.
It is a super-2 number, since 2×643339830012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (64333983011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32166991500 + 32166991501.
It is an arithmetic number, because the mean of its divisors is an integer number (32166991501).
Almost surely, 264333983001 is an apocalyptic number.
It is an amenable number.
64333983001 is a deficient number, since it is larger than the sum of its proper divisors (1).
64333983001 is an equidigital number, since it uses as much as digits as its factorization.
64333983001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 40.
The spelling of 64333983001 in words is "sixty-four billion, three hundred thirty-three million, nine hundred eighty-three thousand, one".
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