Base | Representation |
---|---|
bin | 11101010001101110100110… |
… | …00011010000010011101011 |
3 | 22102221202010001002100120102 |
4 | 32220313103003100103223 |
5 | 31414303342221124142 |
6 | 344532044523020015 |
7 | 16363234244504516 |
oct | 1650672303202353 |
9 | 272852101070512 |
10 | 64380805645547 |
11 | 19571823423516 |
12 | 727952166a60b |
13 | 29c01124b9071 |
14 | 11c809494bd7d |
15 | 769a5c2ca532 |
hex | 3a8dd30d04eb |
64380805645547 has 2 divisors, whose sum is σ = 64380805645548. Its totient is φ = 64380805645546.
The previous prime is 64380805645537. The next prime is 64380805645591. The reversal of 64380805645547 is 74554650808346.
64380805645547 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 64380805645547 - 28 = 64380805645291 is a prime.
It is not a weakly prime, because it can be changed into another prime (64380805645537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32190402822773 + 32190402822774.
It is an arithmetic number, because the mean of its divisors is an integer number (32190402822774).
Almost surely, 264380805645547 is an apocalyptic number.
64380805645547 is a deficient number, since it is larger than the sum of its proper divisors (1).
64380805645547 is an equidigital number, since it uses as much as digits as its factorization.
64380805645547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072000, while the sum is 65.
The spelling of 64380805645547 in words is "sixty-four trillion, three hundred eighty billion, eight hundred five million, six hundred forty-five thousand, five hundred forty-seven".
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