Base | Representation |
---|---|
bin | 101110110111011000111… |
… | …1100110001111100101111 |
3 | 211210202201020001111200122 |
4 | 1131232301330301330233 |
5 | 1321012424204232132 |
6 | 21411004115515155 |
7 | 1233233330125565 |
oct | 135566174617457 |
9 | 24722636044618 |
10 | 6441141477167 |
11 | 2063744497551 |
12 | 8804052b8abb |
13 | 379521394367 |
14 | 183a77db7a35 |
15 | b2837693912 |
hex | 5dbb1f31f2f |
6441141477167 has 4 divisors (see below), whose sum is σ = 6441147039360. Its totient is φ = 6441135914976.
The previous prime is 6441141477157. The next prime is 6441141477191. The reversal of 6441141477167 is 7617741411446.
6441141477167 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 6441141477167 - 232 = 6436846509871 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6441141477157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315338 + ... + 3603015.
It is an arithmetic number, because the mean of its divisors is an integer number (1610286759840).
Almost surely, 26441141477167 is an apocalyptic number.
6441141477167 is a deficient number, since it is larger than the sum of its proper divisors (5562193).
6441141477167 is a wasteful number, since it uses less digits than its factorization.
6441141477167 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5562192.
The product of its digits is 3161088, while the sum is 53.
The spelling of 6441141477167 in words is "six trillion, four hundred forty-one billion, one hundred forty-one million, four hundred seventy-seven thousand, one hundred sixty-seven".
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