Base | Representation |
---|---|
bin | 101110110111110010111… |
… | …1011111101000011010011 |
3 | 211210211222000020210012011 |
4 | 1131233211323331003103 |
5 | 1321021221000110411 |
6 | 21411230434043351 |
7 | 1233264050523544 |
oct | 135574573750323 |
9 | 24724860223164 |
10 | 6442013675731 |
11 | 2064051860207 |
12 | 880609419557 |
13 | 37962cca569a |
14 | 183b1bb784cb |
15 | b288902cc21 |
hex | 5dbe5efd0d3 |
6442013675731 has 2 divisors, whose sum is σ = 6442013675732. Its totient is φ = 6442013675730.
The previous prime is 6442013675639. The next prime is 6442013675791. The reversal of 6442013675731 is 1375763102446.
6442013675731 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6442013675731 - 213 = 6442013667539 is a prime.
It is a super-2 number, since 2×64420136757312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6442013675791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3221006837865 + 3221006837866.
It is an arithmetic number, because the mean of its divisors is an integer number (3221006837866).
Almost surely, 26442013675731 is an apocalyptic number.
6442013675731 is a deficient number, since it is larger than the sum of its proper divisors (1).
6442013675731 is an equidigital number, since it uses as much as digits as its factorization.
6442013675731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2540160, while the sum is 49.
The spelling of 6442013675731 in words is "six trillion, four hundred forty-two billion, thirteen million, six hundred seventy-five thousand, seven hundred thirty-one".
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