Base | Representation |
---|---|
bin | 101110111011100011010… |
… | …0100001111010101001001 |
3 | 211211121202222101100020101 |
4 | 1131313012210033111021 |
5 | 1321134224242100131 |
6 | 21415042525325401 |
7 | 1234000633304404 |
oct | 135670644172511 |
9 | 24747688340211 |
10 | 6450077300041 |
11 | 206750a534531 |
12 | 882099a06861 |
13 | 37a31676430b |
14 | 184284a84d3b |
15 | b2babde4c61 |
hex | 5ddc690f549 |
6450077300041 has 2 divisors, whose sum is σ = 6450077300042. Its totient is φ = 6450077300040.
The previous prime is 6450077300033. The next prime is 6450077300053. The reversal of 6450077300041 is 1400037700546.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4086543110400 + 2363534189641 = 2021520^2 + 1537379^2 .
It is a cyclic number.
It is not a de Polignac number, because 6450077300041 - 23 = 6450077300033 is a prime.
It is not a weakly prime, because it can be changed into another prime (6450077300081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3225038650020 + 3225038650021.
It is an arithmetic number, because the mean of its divisors is an integer number (3225038650021).
Almost surely, 26450077300041 is an apocalyptic number.
It is an amenable number.
6450077300041 is a deficient number, since it is larger than the sum of its proper divisors (1).
6450077300041 is an equidigital number, since it uses as much as digits as its factorization.
6450077300041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 70560, while the sum is 37.
The spelling of 6450077300041 in words is "six trillion, four hundred fifty billion, seventy-seven million, three hundred thousand, forty-one".
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