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645113000842 = 2322556500421
BaseRepresentation
bin10010110001100111011…
…10110011001110001010
32021200011000220221120021
421120303232303032022
541032142412011332
61212205534251054
764415334013552
oct11306356631612
92250130827507
10645113000842
1122965551a872
12a503b056a8a
1348aac0b484b
142331b92a162
1511baa67cc97
hex9633bb338a

645113000842 has 4 divisors (see below), whose sum is σ = 967669501266. Its totient is φ = 322556500420.

The previous prime is 645113000747. The next prime is 645113000923. The reversal of 645113000842 is 248000311546.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 644582573881 + 530426961 = 802859^2 + 23031^2 .

It is a junction number, because it is equal to n+sod(n) for n = 645113000798 and 645113000807.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161278250209 + ... + 161278250212.

Almost surely, 2645113000842 is an apocalyptic number.

645113000842 is a deficient number, since it is larger than the sum of its proper divisors (322556500424).

645113000842 is a wasteful number, since it uses less digits than its factorization.

645113000842 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 322556500423.

The product of its (nonzero) digits is 23040, while the sum is 34.

The spelling of 645113000842 in words is "six hundred forty-five billion, one hundred thirteen million, eight hundred forty-two", and thus it is an aban number.

Divisors: 1 2 322556500421 645113000842