Base | Representation |
---|---|
bin | 111100000110101011… |
… | …010010011101000001 |
3 | 20011120122211220222111 |
4 | 330012223102131001 |
5 | 2024132322124023 |
6 | 45351521335321 |
7 | 4443163242013 |
oct | 740653223501 |
9 | 204518756874 |
10 | 64536520513 |
11 | 25408202073 |
12 | 10611197541 |
13 | 611657c85a |
14 | 31a31881b3 |
15 | 1a2ab5700d |
hex | f06ad2741 |
64536520513 has 2 divisors, whose sum is σ = 64536520514. Its totient is φ = 64536520512.
The previous prime is 64536520439. The next prime is 64536520519. The reversal of 64536520513 is 31502563546.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 63936662449 + 599858064 = 252857^2 + 24492^2 .
It is a cyclic number.
It is not a de Polignac number, because 64536520513 - 29 = 64536520001 is a prime.
It is not a weakly prime, because it can be changed into another prime (64536520519) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32268260256 + 32268260257.
It is an arithmetic number, because the mean of its divisors is an integer number (32268260257).
Almost surely, 264536520513 is an apocalyptic number.
It is an amenable number.
64536520513 is a deficient number, since it is larger than the sum of its proper divisors (1).
64536520513 is an equidigital number, since it uses as much as digits as its factorization.
64536520513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 64536520513 in words is "sixty-four billion, five hundred thirty-six million, five hundred twenty thousand, five hundred thirteen".
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