Base | Representation |
---|---|
bin | 11101010110010001101011… |
… | …10010011000110100011011 |
3 | 22110111200111010201110002001 |
4 | 32223020311302120310123 |
5 | 31424333420213203003 |
6 | 345131531542021431 |
7 | 16410436013150545 |
oct | 1653106562306433 |
9 | 273450433643061 |
10 | 64537080991003 |
11 | 19622027817585 |
12 | 72a3875a17877 |
13 | 2a01a88bac18a |
14 | 11d187b904695 |
15 | 76db56c8161d |
hex | 3ab235c98d1b |
64537080991003 has 2 divisors, whose sum is σ = 64537080991004. Its totient is φ = 64537080991002.
The previous prime is 64537080990979. The next prime is 64537080991037. The reversal of 64537080991003 is 30019908073546.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64537080991003 is a prime.
It is not a weakly prime, because it can be changed into another prime (64537080991073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32268540495501 + 32268540495502.
It is an arithmetic number, because the mean of its divisors is an integer number (32268540495502).
Almost surely, 264537080991003 is an apocalyptic number.
64537080991003 is a deficient number, since it is larger than the sum of its proper divisors (1).
64537080991003 is an equidigital number, since it uses as much as digits as its factorization.
64537080991003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4898880, while the sum is 55.
The spelling of 64537080991003 in words is "sixty-four trillion, five hundred thirty-seven billion, eighty million, nine hundred ninety-one thousand, three".
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