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64537080991023 = 321512360330341
BaseRepresentation
bin11101010110010001101011…
…10010011000110100101111
322110111200111010201110002210
432223020311302120310233
531424333420213203043
6345131531542021503
716410436013150604
oct1653106562306457
9273450433643083
1064537080991023
11196220278175a3
1272a3875a17893
132a01a88bac1a4
1411d187b9046ab
1576db56c81633
hex3ab235c98d2f

64537080991023 has 4 divisors (see below), whose sum is σ = 86049441321368. Its totient is φ = 43024720660680.

The previous prime is 64537080991003. The next prime is 64537080991037. The reversal of 64537080991023 is 32019908073546.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-64537080991023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (64537080991003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10756180165168 + ... + 10756180165173.

It is an arithmetic number, because the mean of its divisors is an integer number (21512360330342).

It is a 1-persistent number, because it is pandigital, but 2⋅64537080991023 = 129074161982046 is not.

Almost surely, 264537080991023 is an apocalyptic number.

64537080991023 is a deficient number, since it is larger than the sum of its proper divisors (21512360330345).

64537080991023 is a wasteful number, since it uses less digits than its factorization.

64537080991023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21512360330344.

The product of its (nonzero) digits is 9797760, while the sum is 57.

The spelling of 64537080991023 in words is "sixty-four trillion, five hundred thirty-seven billion, eighty million, nine hundred ninety-one thousand, twenty-three".

Divisors: 1 3 21512360330341 64537080991023