Base | Representation |
---|---|
bin | 100110011101111… |
… | …110101011011001 |
3 | 1122222102100220122 |
4 | 212131332223121 |
5 | 2310210034423 |
6 | 144013003025 |
7 | 21664515401 |
oct | 4635765331 |
9 | 1588370818 |
10 | 645393113 |
11 | 301342442 |
12 | 160183475 |
13 | a3930121 |
14 | 61a01801 |
15 | 3b9d78c8 |
hex | 2677ead9 |
645393113 has 2 divisors, whose sum is σ = 645393114. Its totient is φ = 645393112.
The previous prime is 645393101. The next prime is 645393157. The reversal of 645393113 is 311393546.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 631165129 + 14227984 = 25123^2 + 3772^2 .
It is a cyclic number.
It is not a de Polignac number, because 645393113 - 24 = 645393097 is a prime.
It is equal to p33566165 and since 645393113 and 33566165 have the same sum of digits, it is a Honaker prime.
It is not a weakly prime, because it can be changed into another prime (645393713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 322696556 + 322696557.
It is an arithmetic number, because the mean of its divisors is an integer number (322696557).
Almost surely, 2645393113 is an apocalyptic number.
It is an amenable number.
645393113 is a deficient number, since it is larger than the sum of its proper divisors (1).
645393113 is an equidigital number, since it uses as much as digits as its factorization.
645393113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 29160, while the sum is 35.
The square root of 645393113 is about 25404.5884241410. The cubic root of 645393113 is about 864.1877561386.
The spelling of 645393113 in words is "six hundred forty-five million, three hundred ninety-three thousand, one hundred thirteen".
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