Base | Representation |
---|---|
bin | 101110111101111111000… |
… | …1111110001001100011101 |
3 | 211212010021101220102022111 |
4 | 1131323332033301030131 |
5 | 1321230431421100432 |
6 | 21421305443514021 |
7 | 1234244340162124 |
oct | 135737617611435 |
9 | 24763241812274 |
10 | 6455306425117 |
11 | 2069753207600 |
12 | 8830b9088911 |
13 | 37a96ac06b74 |
14 | 18461d34aabb |
15 | b2db600a347 |
hex | 5defe3f131d |
6455306425117 has 24 divisors (see below), whose sum is σ = 7486280081280. Its totient is φ = 5546693908800.
The previous prime is 6455306425111. The next prime is 6455306425213. The reversal of 6455306425117 is 7115246035546.
It is not a de Polignac number, because 6455306425117 - 239 = 5905550611229 is a prime.
It is a super-4 number, since 4×64553064251174 (a number of 52 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6455306425111) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2266528 + ... + 4248265.
It is an arithmetic number, because the mean of its divisors is an integer number (311928336720).
Almost surely, 26455306425117 is an apocalyptic number.
It is an amenable number.
6455306425117 is a deficient number, since it is larger than the sum of its proper divisors (1030973656163).
6455306425117 is a wasteful number, since it uses less digits than its factorization.
6455306425117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6515265 (or 6515254 counting only the distinct ones).
The product of its (nonzero) digits is 3024000, while the sum is 49.
The spelling of 6455306425117 in words is "six trillion, four hundred fifty-five billion, three hundred six million, four hundred twenty-five thousand, one hundred seventeen".
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