Base | Representation |
---|---|
bin | 11101010111010011000000… |
… | …11110110010010101010011 |
3 | 22110122001000122102220020021 |
4 | 32223221200132302111103 |
5 | 31430422234143330113 |
6 | 345200012302524311 |
7 | 16413120150333415 |
oct | 1653514036622523 |
9 | 273561018386207 |
10 | 64572157011283 |
11 | 19635997270799 |
12 | 72aa624896697 |
13 | 2a05188a9b96c |
14 | 11d344815c9b5 |
15 | 76ea0b32b48d |
hex | 3aba607b2553 |
64572157011283 has 2 divisors, whose sum is σ = 64572157011284. Its totient is φ = 64572157011282.
The previous prime is 64572157011233. The next prime is 64572157011319. The reversal of 64572157011283 is 38211075127546.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64572157011283 is a prime.
It is a super-2 number, since 2×645721570112832 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 64572157011283.
It is not a weakly prime, because it can be changed into another prime (64572157011233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32286078505641 + 32286078505642.
It is an arithmetic number, because the mean of its divisors is an integer number (32286078505642).
Almost surely, 264572157011283 is an apocalyptic number.
64572157011283 is a deficient number, since it is larger than the sum of its proper divisors (1).
64572157011283 is an equidigital number, since it uses as much as digits as its factorization.
64572157011283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2822400, while the sum is 52.
The spelling of 64572157011283 in words is "sixty-four trillion, five hundred seventy-two billion, one hundred fifty-seven million, eleven thousand, two hundred eighty-three".
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