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6478120681313 is a prime number
BaseRepresentation
bin101111001000100111000…
…0101001111111101100001
3211221022011100221201022012
41132101032011033331201
51322114142343300223
621440001344322305
71236012604151441
oct136211605177541
924838140851265
106478120681313
1120783a0270996
12887605613395
1337cb65660948
141857852c8121
15b379dd79c78
hex5e44e14ff61

6478120681313 has 2 divisors, whose sum is σ = 6478120681314. Its totient is φ = 6478120681312.

The previous prime is 6478120681271. The next prime is 6478120681379. The reversal of 6478120681313 is 3131860218746.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4971040353889 + 1507080327424 = 2229583^2 + 1227632^2 .

It is a cyclic number.

It is not a de Polignac number, because 6478120681313 - 214 = 6478120664929 is a prime.

It is not a weakly prime, because it can be changed into another prime (6478120683313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3239060340656 + 3239060340657.

It is an arithmetic number, because the mean of its divisors is an integer number (3239060340657).

Almost surely, 26478120681313 is an apocalyptic number.

It is an amenable number.

6478120681313 is a deficient number, since it is larger than the sum of its proper divisors (1).

6478120681313 is an equidigital number, since it uses as much as digits as its factorization.

6478120681313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1161216, while the sum is 50.

The spelling of 6478120681313 in words is "six trillion, four hundred seventy-eight billion, one hundred twenty million, six hundred eighty-one thousand, three hundred thirteen".