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64850113 is a prime number
BaseRepresentation
bin1111011101100…
…0100011000001
311112000201122001
43313120203001
5113100200423
610233544001
71415134246
oct367304301
9145021561
1064850113
1133673939
1219875001
1310587763
1488815cd
155a5ecad
hex3dd88c1

64850113 has 2 divisors, whose sum is σ = 64850114. Its totient is φ = 64850112.

The previous prime is 64850101. The next prime is 64850129. The reversal of 64850113 is 31105846.

64850113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42354064 + 22496049 = 6508^2 + 4743^2 .

It is a cyclic number.

It is not a de Polignac number, because 64850113 - 25 = 64850081 is a prime.

It is a super-2 number, since 2×648501132 = 8411074312225538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (64850143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32425056 + 32425057.

It is an arithmetic number, because the mean of its divisors is an integer number (32425057).

Almost surely, 264850113 is an apocalyptic number.

It is an amenable number.

64850113 is a deficient number, since it is larger than the sum of its proper divisors (1).

64850113 is an equidigital number, since it uses as much as digits as its factorization.

64850113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

The square root of 64850113 is about 8052.9567861749. The cubic root of 64850113 is about 401.7632843988.

Adding to 64850113 its reverse (31105846), we get a palindrome (95955959).

The spelling of 64850113 in words is "sixty-four million, eight hundred fifty thousand, one hundred thirteen".