Base | Representation |
---|---|
bin | 111100100001111011… |
… | …110100110000010011 |
3 | 20012202112101011120201 |
4 | 330201323310300103 |
5 | 2031101410341042 |
6 | 45505135320031 |
7 | 4460415345265 |
oct | 744173646023 |
9 | 205675334521 |
10 | 64993840147 |
11 | 25622368085 |
12 | 1071a380017 |
13 | 618a2400a2 |
14 | 3207bcdb35 |
15 | 1a55d8e1b7 |
hex | f21ef4c13 |
64993840147 has 2 divisors, whose sum is σ = 64993840148. Its totient is φ = 64993840146.
The previous prime is 64993840111. The next prime is 64993840157. The reversal of 64993840147 is 74104839946.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64993840147 - 27 = 64993840019 is a prime.
It is not a weakly prime, because it can be changed into another prime (64993840157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32496920073 + 32496920074.
It is an arithmetic number, because the mean of its divisors is an integer number (32496920074).
Almost surely, 264993840147 is an apocalyptic number.
64993840147 is a deficient number, since it is larger than the sum of its proper divisors (1).
64993840147 is an equidigital number, since it uses as much as digits as its factorization.
64993840147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5225472, while the sum is 55.
The spelling of 64993840147 in words is "sixty-four billion, nine hundred ninety-three million, eight hundred forty thousand, one hundred forty-seven".
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