6500211315131 has 2 divisors, whose sum is σ = 6500211315132. Its totient is φ = 6500211315130.

The previous prime is 6500211314959. The next prime is 6500211315137. The reversal of 6500211315131 is 1315131120056.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 6500211315131 - 2¹⁴ = 6500211298747 is a prime.

It is a super-2 number, since 2×6500211315131² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 6500211315094 and 6500211315103.

It is not a weakly prime, because it can be changed into another prime (6500211315137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250105657565 + 3250105657566.

It is an arithmetic number, because the mean of its divisors is an integer number (3250105657566).

Almost surely, 2^{6500211315131} is an apocalyptic number.

6500211315131 is a deficient number, since it is larger than the sum of its proper divisors (1).

6500211315131 is an equidigital number, since it uses as much as digits as its factorization.

6500211315131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 29.

Adding to 6500211315131 its reverse (1315131120056), we get a palindrome (7815342435187).

The spelling of 6500211315131 in words is "six trillion, five hundred billion, two hundred eleven million, three hundred fifteen thousand, one hundred thirty-one".