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650134403 is a prime number
BaseRepresentation
bin100110110000000…
…100001110000011
31200022100020201222
4212300010032003
52312413300103
6144302345255
722053023402
oct4660041603
91608306658
10650134403
11303a90666
1216188b22b
13a4900219
14624b7639
153c122638
hex26c04383

650134403 has 2 divisors, whose sum is σ = 650134404. Its totient is φ = 650134402.

The previous prime is 650134391. The next prime is 650134439. The reversal of 650134403 is 304431056.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 650134403 - 26 = 650134339 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (650134453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325067201 + 325067202.

It is an arithmetic number, because the mean of its divisors is an integer number (325067202).

Almost surely, 2650134403 is an apocalyptic number.

650134403 is a deficient number, since it is larger than the sum of its proper divisors (1).

650134403 is an equidigital number, since it uses as much as digits as its factorization.

650134403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 650134403 is about 25497.7332914124. The cubic root of 650134403 is about 866.2988064234.

Adding to 650134403 its reverse (304431056), we get a palindrome (954565459).

It can be divided in two parts, 6501 and 34403, that added together give a palindrome (40904).

The spelling of 650134403 in words is "six hundred fifty million, one hundred thirty-four thousand, four hundred three".