Base | Representation |
---|---|
bin | 10010111010111110000… |
… | …10010011101011110011 |
3 | 2022011002222202122100111 |
4 | 21131133002103223303 |
5 | 41122433413032011 |
6 | 1214400114402151 |
7 | 64653640042162 |
oct | 11353702235363 |
9 | 2264088678314 |
10 | 650134502131 |
11 | 2307a1a83034 |
12 | a6000890357 |
13 | 493cc530c9a |
14 | 236767c73d9 |
15 | 11da1430121 |
hex | 975f093af3 |
650134502131 has 2 divisors, whose sum is σ = 650134502132. Its totient is φ = 650134502130.
The previous prime is 650134502033. The next prime is 650134502197. The reversal of 650134502131 is 131205431056.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 650134502131 - 221 = 650132404979 is a prime.
It is a super-2 number, since 2×6501345021312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 650134502093 and 650134502102.
It is not a weakly prime, because it can be changed into another prime (650134542131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325067251065 + 325067251066.
It is an arithmetic number, because the mean of its divisors is an integer number (325067251066).
Almost surely, 2650134502131 is an apocalyptic number.
650134502131 is a deficient number, since it is larger than the sum of its proper divisors (1).
650134502131 is an equidigital number, since it uses as much as digits as its factorization.
650134502131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 650134502131 its reverse (131205431056), we get a palindrome (781339933187).
The spelling of 650134502131 in words is "six hundred fifty billion, one hundred thirty-four million, five hundred two thousand, one hundred thirty-one".
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