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650555016161 is a prime number
BaseRepresentation
bin10010111011110000001…
…10011100001111100001
32022012012022000222011012
421131320012130033201
541124314041004121
61214505535430305
765000234253461
oct11357006341741
92265168028135
10650555016161
1123099838a496
12a60b9685395
13494686a595b
14236b65abba1
1511dc82e6c5b
hex977819c3e1

650555016161 has 2 divisors, whose sum is σ = 650555016162. Its totient is φ = 650555016160.

The previous prime is 650555016157. The next prime is 650555016253. The reversal of 650555016161 is 161610555056.

650555016161 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 624959815936 + 25595200225 = 790544^2 + 159985^2 .

It is a cyclic number.

It is not a de Polignac number, because 650555016161 - 22 = 650555016157 is a prime.

It is not a weakly prime, because it can be changed into another prime (650555016131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325277508080 + 325277508081.

It is an arithmetic number, because the mean of its divisors is an integer number (325277508081).

Almost surely, 2650555016161 is an apocalyptic number.

It is an amenable number.

650555016161 is a deficient number, since it is larger than the sum of its proper divisors (1).

650555016161 is an equidigital number, since it uses as much as digits as its factorization.

650555016161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135000, while the sum is 41.

The spelling of 650555016161 in words is "six hundred fifty billion, five hundred fifty-five million, sixteen thousand, one hundred sixty-one".