Base | Representation |
---|---|
bin | 111100101000101010… |
… | …000100110111010011 |
3 | 20020001101121101111111 |
4 | 330220222010313103 |
5 | 2031314244044201 |
6 | 45524244554151 |
7 | 4463255131063 |
oct | 745052046723 |
9 | 206041541444 |
10 | 65106628051 |
11 | 2567aaa3323 |
12 | 107500b2957 |
13 | 61a77103aa |
14 | 3218b8d3a3 |
15 | 1a60c1cb51 |
hex | f28a84dd3 |
65106628051 has 2 divisors, whose sum is σ = 65106628052. Its totient is φ = 65106628050.
The previous prime is 65106628043. The next prime is 65106628061. The reversal of 65106628051 is 15082660156.
65106628051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 65106628051 - 23 = 65106628043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 65106627995 and 65106628013.
It is not a weakly prime, because it can be changed into another prime (65106628001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32553314025 + 32553314026.
It is an arithmetic number, because the mean of its divisors is an integer number (32553314026).
Almost surely, 265106628051 is an apocalyptic number.
65106628051 is a deficient number, since it is larger than the sum of its proper divisors (1).
65106628051 is an equidigital number, since it uses as much as digits as its factorization.
65106628051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 65106628051 in words is "sixty-five billion, one hundred six million, six hundred twenty-eight thousand, fifty-one".
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