Base | Representation |
---|---|
bin | 11101100111000101110010… |
… | …01100110010010111101100 |
3 | 22112112220201011022020102220 |
4 | 32303202321030302113230 |
5 | 32013320113201004424 |
6 | 350253155324315340 |
7 | 16500250504140225 |
oct | 1663427114622754 |
9 | 275486634266386 |
10 | 65114811344364 |
11 | 19825044511a31 |
12 | 737782a6a2b50 |
13 | 2a443b9b86682 |
14 | 121180629624c |
15 | 77dbbb9aa579 |
hex | 3b38b93325ec |
65114811344364 has 12 divisors (see below), whose sum is σ = 151934559803544. Its totient is φ = 21704937114784.
The previous prime is 65114811344327. The next prime is 65114811344371. The reversal of 65114811344364 is 46344311841156.
It is a tau number, because it is divible by the number of its divisors (12).
It is a super-2 number, since 2×651148113443642 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2713117139337 + ... + 2713117139360.
It is an arithmetic number, because the mean of its divisors is an integer number (12661213316962).
Almost surely, 265114811344364 is an apocalyptic number.
It is an amenable number.
65114811344364 is an abundant number, since it is smaller than the sum of its proper divisors (86819748459180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
65114811344364 is a wasteful number, since it uses less digits than its factorization.
65114811344364 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5426234278704 (or 5426234278702 counting only the distinct ones).
The product of its digits is 3317760, while the sum is 51.
The spelling of 65114811344364 in words is "sixty-five trillion, one hundred fourteen billion, eight hundred eleven million, three hundred forty-four thousand, three hundred sixty-four".
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