Base | Representation |
---|---|
bin | 111100101111000100… |
… | …001101100100000011 |
3 | 20020022212220200220101 |
4 | 330233010031210003 |
5 | 2032024310031343 |
6 | 45543045223231 |
7 | 4466032031662 |
oct | 745704154403 |
9 | 206285820811 |
10 | 65214142723 |
11 | 25725757724 |
12 | 10780101b17 |
13 | 61c3a85442 |
14 | 3229178dd9 |
15 | 1a6a3a8e4d |
hex | f2f10d903 |
65214142723 has 2 divisors, whose sum is σ = 65214142724. Its totient is φ = 65214142722.
The previous prime is 65214142717. The next prime is 65214142759. The reversal of 65214142723 is 32724141256.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 65214142723 - 29 = 65214142211 is a prime.
It is a super-2 number, since 2×652141427232 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (65214142223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32607071361 + 32607071362.
It is an arithmetic number, because the mean of its divisors is an integer number (32607071362).
Almost surely, 265214142723 is an apocalyptic number.
65214142723 is a deficient number, since it is larger than the sum of its proper divisors (1).
65214142723 is an equidigital number, since it uses as much as digits as its factorization.
65214142723 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 80640, while the sum is 37.
Adding to 65214142723 its reverse (32724141256), we get a palindrome (97938283979).
The spelling of 65214142723 in words is "sixty-five billion, two hundred fourteen million, one hundred forty-two thousand, seven hundred twenty-three".
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