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6541764764713 is a prime number
BaseRepresentation
bin101111100110001111110…
…0100001010010000101001
3212011101102211112010201021
41133030133210022100221
51324140013234432323
621525124550052441
71243425013014133
oct137143744122051
925141384463637
106541764764713
1120a238a736822
12897a0794a121
13385b690642a9
141888a1b24053
15b527649b05d
hex5f31f90a429

6541764764713 has 2 divisors, whose sum is σ = 6541764764714. Its totient is φ = 6541764764712.

The previous prime is 6541764764681. The next prime is 6541764764719. The reversal of 6541764764713 is 3174674671456.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6521853579264 + 19911185449 = 2553792^2 + 141107^2 .

It is a cyclic number.

It is not a de Polignac number, because 6541764764713 - 25 = 6541764764681 is a prime.

It is a super-3 number, since 3×65417647647133 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (6541764764719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3270882382356 + 3270882382357.

It is an arithmetic number, because the mean of its divisors is an integer number (3270882382357).

Almost surely, 26541764764713 is an apocalyptic number.

It is an amenable number.

6541764764713 is a deficient number, since it is larger than the sum of its proper divisors (1).

6541764764713 is an equidigital number, since it uses as much as digits as its factorization.

6541764764713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 71124480, while the sum is 61.

The spelling of 6541764764713 in words is "six trillion, five hundred forty-one billion, seven hundred sixty-four million, seven hundred sixty-four thousand, seven hundred thirteen".