Base | Representation |
---|---|
bin | 101111100110001111110… |
… | …0100001010010000101001 |
3 | 212011101102211112010201021 |
4 | 1133030133210022100221 |
5 | 1324140013234432323 |
6 | 21525124550052441 |
7 | 1243425013014133 |
oct | 137143744122051 |
9 | 25141384463637 |
10 | 6541764764713 |
11 | 20a238a736822 |
12 | 897a0794a121 |
13 | 385b690642a9 |
14 | 1888a1b24053 |
15 | b527649b05d |
hex | 5f31f90a429 |
6541764764713 has 2 divisors, whose sum is σ = 6541764764714. Its totient is φ = 6541764764712.
The previous prime is 6541764764681. The next prime is 6541764764719. The reversal of 6541764764713 is 3174674671456.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6521853579264 + 19911185449 = 2553792^2 + 141107^2 .
It is a cyclic number.
It is not a de Polignac number, because 6541764764713 - 25 = 6541764764681 is a prime.
It is a super-3 number, since 3×65417647647133 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (6541764764719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3270882382356 + 3270882382357.
It is an arithmetic number, because the mean of its divisors is an integer number (3270882382357).
Almost surely, 26541764764713 is an apocalyptic number.
It is an amenable number.
6541764764713 is a deficient number, since it is larger than the sum of its proper divisors (1).
6541764764713 is an equidigital number, since it uses as much as digits as its factorization.
6541764764713 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 71124480, while the sum is 61.
The spelling of 6541764764713 in words is "six trillion, five hundred forty-one billion, seven hundred sixty-four million, seven hundred sixty-four thousand, seven hundred thirteen".
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