Base | Representation |
---|---|
bin | 101111100110101001111… |
… | …0000001001101000101001 |
3 | 212011110200212001010001011 |
4 | 1133031103300021220221 |
5 | 1324143311410314423 |
6 | 21525351504223521 |
7 | 1243455504104416 |
oct | 137152360115051 |
9 | 25143625033034 |
10 | 6542640323113 |
11 | 20a2799994804 |
12 | 89801100aba1 |
13 | 385c7858099b |
14 | 18894611b10d |
15 | b52c829ab0d |
hex | 5f353c09a29 |
6542640323113 has 2 divisors, whose sum is σ = 6542640323114. Its totient is φ = 6542640323112.
The previous prime is 6542640323099. The next prime is 6542640323123. The reversal of 6542640323113 is 3113230462456.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4196483355024 + 2346156968089 = 2048532^2 + 1531717^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6542640323113 is a prime.
It is a super-2 number, since 2×65426403231132 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6542640323123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3271320161556 + 3271320161557.
It is an arithmetic number, because the mean of its divisors is an integer number (3271320161557).
Almost surely, 26542640323113 is an apocalyptic number.
It is an amenable number.
6542640323113 is a deficient number, since it is larger than the sum of its proper divisors (1).
6542640323113 is an equidigital number, since it uses as much as digits as its factorization.
6542640323113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 40.
Adding to 6542640323113 its reverse (3113230462456), we get a palindrome (9655870785569).
The spelling of 6542640323113 in words is "six trillion, five hundred forty-two billion, six hundred forty million, three hundred twenty-three thousand, one hundred thirteen".
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