Base | Representation |
---|---|
bin | 101111101010000101111… |
… | …1110100000011001101001 |
3 | 212012011202120121111022021 |
4 | 1133110023332200121221 |
5 | 1324303423132431132 |
6 | 21533012422224441 |
7 | 1244136515616226 |
oct | 137241376403151 |
9 | 25164676544267 |
10 | 6550026061417 |
11 | 20a5939a53263 |
12 | 899532585121 |
13 | 386884773937 |
14 | 189046da894d |
15 | b55ab8ac997 |
hex | 5f50bfa0669 |
6550026061417 has 2 divisors, whose sum is σ = 6550026061418. Its totient is φ = 6550026061416.
The previous prime is 6550026061387. The next prime is 6550026061433. The reversal of 6550026061417 is 7141606200556.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6539455959696 + 10570101721 = 2557236^2 + 102811^2 .
It is a cyclic number.
It is not a de Polignac number, because 6550026061417 - 231 = 6547878577769 is a prime.
It is not a weakly prime, because it can be changed into another prime (6550026061457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275013030708 + 3275013030709.
It is an arithmetic number, because the mean of its divisors is an integer number (3275013030709).
Almost surely, 26550026061417 is an apocalyptic number.
It is an amenable number.
6550026061417 is a deficient number, since it is larger than the sum of its proper divisors (1).
6550026061417 is an equidigital number, since it uses as much as digits as its factorization.
6550026061417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 6550026061417 in words is "six trillion, five hundred fifty billion, twenty-six million, sixty-one thousand, four hundred seventeen".
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