Base | Representation |
---|---|
bin | 1100001100111001… |
… | …11000000111010001 |
3 | 121220112021020021010 |
4 | 12012130320013101 |
5 | 101403433342423 |
6 | 3002003521133 |
7 | 321221616261 |
oct | 60634700721 |
9 | 17815236233 |
10 | 6550684113 |
11 | 2861765a26 |
12 | 13299891a9 |
13 | 8051b875c |
14 | 461dd97a1 |
15 | 285163693 |
hex | 1867381d1 |
6550684113 has 16 divisors (see below), whose sum is σ = 8939975616. Its totient is φ = 4264317120.
The previous prime is 6550684109. The next prime is 6550684117. The reversal of 6550684113 is 3114860556.
6550684113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (6550684109) and next prime (6550684117).
It is not a de Polignac number, because 6550684113 - 22 = 6550684109 is a prime.
It is a super-2 number, since 2×65506841132 = 85822924696621193538, which contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (6550684117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 689431 + ... + 698867.
It is an arithmetic number, because the mean of its divisors is an integer number (558748476).
Almost surely, 26550684113 is an apocalyptic number.
It is an amenable number.
6550684113 is a deficient number, since it is larger than the sum of its proper divisors (2389291503).
6550684113 is a wasteful number, since it uses less digits than its factorization.
6550684113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14864.
The product of its (nonzero) digits is 86400, while the sum is 39.
The square root of 6550684113 is about 80936.2966350697. The cubic root of 6550684113 is about 1871.0937687932.
The spelling of 6550684113 in words is "six billion, five hundred fifty million, six hundred eighty-four thousand, one hundred thirteen".
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