Base | Representation |
---|---|
bin | 1111100111111… |
… | …0100111000011 |
3 | 11120022021200102 |
4 | 3321332213003 |
5 | 113233432212 |
6 | 10300313015 |
7 | 1423666313 |
oct | 371764703 |
9 | 146267612 |
10 | 65530307 |
11 | 33a98987 |
12 | 19b4276b |
13 | 1076523b |
14 | 89bb443 |
15 | 5b465c2 |
hex | 3e7e9c3 |
65530307 has 2 divisors, whose sum is σ = 65530308. Its totient is φ = 65530306.
The previous prime is 65530279. The next prime is 65530319. The reversal of 65530307 is 70303556.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 65530307 - 216 = 65464771 is a prime.
It is a super-3 number, since 3×655303073 (a number of 24 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 65530307.
It is not a weakly prime, because it can be changed into another prime (65530397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32765153 + 32765154.
It is an arithmetic number, because the mean of its divisors is an integer number (32765154).
Almost surely, 265530307 is an apocalyptic number.
65530307 is a deficient number, since it is larger than the sum of its proper divisors (1).
65530307 is an equidigital number, since it uses as much as digits as its factorization.
65530307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9450, while the sum is 29.
The square root of 65530307 is about 8095.0791842946. The cubic root of 65530307 is about 403.1630612622.
The spelling of 65530307 in words is "sixty-five million, five hundred thirty thousand, three hundred seven".
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