Base | Representation |
---|---|
bin | 1100001110001000… |
… | …11001011010100011 |
3 | 121221020202120112111 |
4 | 12013010121122203 |
5 | 101414111403011 |
6 | 3003013540151 |
7 | 321405645355 |
oct | 60704313243 |
9 | 17836676474 |
10 | 6561044131 |
11 | 28675a1624 |
12 | 1331344657 |
13 | 8073a5145 |
14 | 4635350d5 |
15 | 28600d121 |
hex | 1871196a3 |
6561044131 has 2 divisors, whose sum is σ = 6561044132. Its totient is φ = 6561044130.
The previous prime is 6561044123. The next prime is 6561044137. The reversal of 6561044131 is 1314401656.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6561044131 - 23 = 6561044123 is a prime.
It is a super-2 number, since 2×65610441312 = 86094600177859090322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 6561044093 and 6561044102.
It is not a weakly prime, because it can be changed into another prime (6561044137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280522065 + 3280522066.
It is an arithmetic number, because the mean of its divisors is an integer number (3280522066).
Almost surely, 26561044131 is an apocalyptic number.
6561044131 is a deficient number, since it is larger than the sum of its proper divisors (1).
6561044131 is an equidigital number, since it uses as much as digits as its factorization.
6561044131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
The square root of 6561044131 is about 81000.2724131222. The cubic root of 6561044131 is about 1872.0796380935.
Adding to 6561044131 its reverse (1314401656), we get a palindrome (7875445787).
The spelling of 6561044131 in words is "six billion, five hundred sixty-one million, forty-four thousand, one hundred thirty-one".
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