Base | Representation |
---|---|
bin | 11101110101100110000000… |
… | …01001111011111101010011 |
3 | 22121022112222211120110222101 |
4 | 32322303000021323331103 |
5 | 32100001204411302201 |
6 | 351314132400021231 |
7 | 16551251610661045 |
oct | 1672630011737523 |
9 | 277275884513871 |
10 | 65613144244051 |
11 | 199a7418438278 |
12 | 7438325301817 |
13 | 2a7c3a6806951 |
14 | 122b99bd19a95 |
15 | 78bb36087d01 |
hex | 3bacc027bf53 |
65613144244051 has 2 divisors, whose sum is σ = 65613144244052. Its totient is φ = 65613144244050.
The previous prime is 65613144244031. The next prime is 65613144244121. The reversal of 65613144244051 is 15044244131656.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 65613144244051 - 217 = 65613144112979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 65613144243992 and 65613144244010.
It is not a weakly prime, because it can be changed into another prime (65613144244001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32806572122025 + 32806572122026.
It is an arithmetic number, because the mean of its divisors is an integer number (32806572122026).
Almost surely, 265613144244051 is an apocalyptic number.
65613144244051 is a deficient number, since it is larger than the sum of its proper divisors (1).
65613144244051 is an equidigital number, since it uses as much as digits as its factorization.
65613144244051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1382400, while the sum is 46.
The spelling of 65613144244051 in words is "sixty-five trillion, six hundred thirteen billion, one hundred forty-four million, two hundred forty-four thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •