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6580248206713 is a prime number
BaseRepresentation
bin101111111000001010101…
…0110110101110101111001
3212022001202210220112201221
41133300111112311311321
51330302322020103323
621554531351512041
71246256453615056
oct137602526656571
925261683815657
106580248206713
112107738625345
128a3367988621
1338968cb77a4c
1418a6b2b1c02d
15b6279c6755d
hex5fc155b5d79

6580248206713 has 2 divisors, whose sum is σ = 6580248206714. Its totient is φ = 6580248206712.

The previous prime is 6580248206683. The next prime is 6580248206809. The reversal of 6580248206713 is 3176028420856.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5121544664889 + 1458703541824 = 2263083^2 + 1207768^2 .

It is a cyclic number.

It is not a de Polignac number, because 6580248206713 - 221 = 6580246109561 is a prime.

It is a super-4 number, since 4×65802482067134 (a number of 52 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (6580248206513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3290124103356 + 3290124103357.

It is an arithmetic number, because the mean of its divisors is an integer number (3290124103357).

Almost surely, 26580248206713 is an apocalyptic number.

It is an amenable number.

6580248206713 is a deficient number, since it is larger than the sum of its proper divisors (1).

6580248206713 is an equidigital number, since it uses as much as digits as its factorization.

6580248206713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3870720, while the sum is 52.

The spelling of 6580248206713 in words is "six trillion, five hundred eighty billion, two hundred forty-eight million, two hundred six thousand, seven hundred thirteen".