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659921130793 is a prime number
BaseRepresentation
bin10011001101001100101…
…11010101010100101001
32100002101001000220000201
421212212113111110221
541303004302141133
61223055200032201
765451314026231
oct11464627252451
92302331026021
10659921130793
11234964301aa1
12a7a92302661
134a2cbc61c12
1423d24486cc1
15122756e1d7d
hex99a65d5529

659921130793 has 2 divisors, whose sum is σ = 659921130794. Its totient is φ = 659921130792.

The previous prime is 659921130689. The next prime is 659921130797. The reversal of 659921130793 is 397031129956.

659921130793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 627378053184 + 32543077609 = 792072^2 + 180397^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-659921130793 is a prime.

It is a super-2 number, since 2×6599211307932 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (659921130797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 329960565396 + 329960565397.

It is an arithmetic number, because the mean of its divisors is an integer number (329960565397).

Almost surely, 2659921130793 is an apocalyptic number.

It is an amenable number.

659921130793 is a deficient number, since it is larger than the sum of its proper divisors (1).

659921130793 is an equidigital number, since it uses as much as digits as its factorization.

659921130793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2755620, while the sum is 55.

The spelling of 659921130793 in words is "six hundred fifty-nine billion, nine hundred twenty-one million, one hundred thirty thousand, seven hundred ninety-three".