Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …11111101100001110100011 |
3 | 22122221212120022101221200112 |
4 | 33001202233133230032203 |
5 | 32130100111111431313 |
6 | 352311120543041535 |
7 | 16626612515052614 |
oct | 1701425737541643 |
9 | 278855508357615 |
10 | 66076721202083 |
11 | 1a065a86558199 |
12 | 74b21402a02ab |
13 | 2ab4014975387 |
14 | 12461b7a43c0b |
15 | 798c192438a8 |
hex | 3c18af7ec3a3 |
66076721202083 has 2 divisors, whose sum is σ = 66076721202084. Its totient is φ = 66076721202082.
The previous prime is 66076721202073. The next prime is 66076721202091. The reversal of 66076721202083 is 38020212767066.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 66076721202083 - 210 = 66076721201059 is a prime.
It is a super-2 number, since 2×660767212020832 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (66076721202073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33038360601041 + 33038360601042.
It is an arithmetic number, because the mean of its divisors is an integer number (33038360601042).
Almost surely, 266076721202083 is an apocalyptic number.
66076721202083 is a deficient number, since it is larger than the sum of its proper divisors (1).
66076721202083 is an equidigital number, since it uses as much as digits as its factorization.
66076721202083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2032128, while the sum is 50.
The spelling of 66076721202083 in words is "sixty-six trillion, seventy-six billion, seven hundred twenty-one million, two hundred two thousand, eighty-three".
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