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6609701122513 is a prime number
BaseRepresentation
bin110000000101111000011…
…1000110011000111010001
3212101212210102202200200021
41200023300320303013101
51331243131441410023
622020242122023441
71251351361355206
oct140136070630721
925355712680607
106609701122513
112119181a72975
128a9007647b81
1338c3a4ab0888
1418bca8635cad
15b6e0082735d
hex602f0e331d1

6609701122513 has 2 divisors, whose sum is σ = 6609701122514. Its totient is φ = 6609701122512.

The previous prime is 6609701122463. The next prime is 6609701122561. The reversal of 6609701122513 is 3152211079066.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5194857483729 + 1414843638784 = 2279223^2 + 1189472^2 .

It is a cyclic number.

It is not a de Polignac number, because 6609701122513 - 213 = 6609701114321 is a prime.

It is a super-2 number, since 2×66097011225132 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 6609701122513.

It is not a weakly prime, because it can be changed into another prime (6609701122313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3304850561256 + 3304850561257.

It is an arithmetic number, because the mean of its divisors is an integer number (3304850561257).

Almost surely, 26609701122513 is an apocalyptic number.

It is an amenable number.

6609701122513 is a deficient number, since it is larger than the sum of its proper divisors (1).

6609701122513 is an equidigital number, since it uses as much as digits as its factorization.

6609701122513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 136080, while the sum is 43.

The spelling of 6609701122513 in words is "six trillion, six hundred nine billion, seven hundred one million, one hundred twenty-two thousand, five hundred thirteen".