Base | Representation |
---|---|
bin | 110000000111011011110… |
… | …0011101101101000000001 |
3 | 212102012101201122200002121 |
4 | 1200032313203231220001 |
5 | 1331321443232322433 |
6 | 22021552550444241 |
7 | 1251530103520126 |
oct | 140166743555001 |
9 | 25365351580077 |
10 | 6613034260993 |
11 | 211a632491176 |
12 | 8a9797963681 |
13 | 38c7b64c6574 |
14 | 18c10319a74d |
15 | b7048273c2d |
hex | 603b78eda01 |
6613034260993 has 2 divisors, whose sum is σ = 6613034260994. Its totient is φ = 6613034260992.
The previous prime is 6613034260979. The next prime is 6613034261023. The reversal of 6613034260993 is 3990624303166.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6607305739024 + 5728521969 = 2570468^2 + 75687^2 .
It is a cyclic number.
It is not a de Polignac number, because 6613034260993 - 217 = 6613034129921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6613034260993.
It is not a weakly prime, because it can be changed into another prime (6613034260913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3306517130496 + 3306517130497.
It is an arithmetic number, because the mean of its divisors is an integer number (3306517130497).
Almost surely, 26613034260993 is an apocalyptic number.
It is an amenable number.
6613034260993 is a deficient number, since it is larger than the sum of its proper divisors (1).
6613034260993 is an equidigital number, since it uses as much as digits as its factorization.
6613034260993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3779136, while the sum is 52.
The spelling of 6613034260993 in words is "six trillion, six hundred thirteen billion, thirty-four million, two hundred sixty thousand, nine hundred ninety-three".
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