Base | Representation |
---|---|
bin | 11110000110101110010100… |
… | …10011111000000000101001 |
3 | 22200101211020001100222222012 |
4 | 33003113022103320000221 |
5 | 32134122113114003113 |
6 | 352444352551205305 |
7 | 16641626315026406 |
oct | 1703271223700051 |
9 | 280354201328865 |
10 | 66201725141033 |
11 | 1a103aa2a6a749 |
12 | 7512407976835 |
13 | 2ac2a4676a161 |
14 | 124c2757952ad |
15 | 79c0d367caa8 |
hex | 3c35ca4f8029 |
66201725141033 has 2 divisors, whose sum is σ = 66201725141034. Its totient is φ = 66201725141032.
The previous prime is 66201725140913. The next prime is 66201725141063. The reversal of 66201725141033 is 33014152710266.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33161439408409 + 33040285732624 = 5758597^2 + 5748068^2 .
It is a cyclic number.
It is not a de Polignac number, because 66201725141033 - 218 = 66201724878889 is a prime.
It is not a weakly prime, because it can be changed into another prime (66201725141063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33100862570516 + 33100862570517.
It is an arithmetic number, because the mean of its divisors is an integer number (33100862570517).
Almost surely, 266201725141033 is an apocalyptic number.
It is an amenable number.
66201725141033 is a deficient number, since it is larger than the sum of its proper divisors (1).
66201725141033 is an equidigital number, since it uses as much as digits as its factorization.
66201725141033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 41.
Adding to 66201725141033 its reverse (33014152710266), we get a palindrome (99215877851299).
The spelling of 66201725141033 in words is "sixty-six trillion, two hundred one billion, seven hundred twenty-five million, one hundred forty-one thousand, thirty-three".
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