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665500005473 is a prime number
BaseRepresentation
bin10011010111100101110…
…01000011010001100001
32100121202211200002100212
421223302321003101201
541400421000133343
61225420530423505
766036465466052
oct11536271032141
92317684602325
10665500005473
11237267449126
12a8b8a731b95
134a9aaa009b4
14242d3392729
15124a0391c18
hex9af2e43461

665500005473 has 2 divisors, whose sum is σ = 665500005474. Its totient is φ = 665500005472.

The previous prime is 665500005449. The next prime is 665500005551. The reversal of 665500005473 is 374500005566.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 642381411169 + 23118594304 = 801487^2 + 152048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-665500005473 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 665500005473.

It is not a weakly prime, because it can be changed into another prime (665500005413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332750002736 + 332750002737.

It is an arithmetic number, because the mean of its divisors is an integer number (332750002737).

Almost surely, 2665500005473 is an apocalyptic number.

It is an amenable number.

665500005473 is a deficient number, since it is larger than the sum of its proper divisors (1).

665500005473 is an equidigital number, since it uses as much as digits as its factorization.

665500005473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 665500005473 in words is "six hundred sixty-five billion, five hundred million, five thousand, four hundred seventy-three".