Base | Representation |
---|---|
bin | 110000011011100000010… |
… | …0100000000000011110001 |
3 | 212120022122111022021220112 |
4 | 1200313000210000003301 |
5 | 1333023231030120101 |
6 | 22053441453151105 |
7 | 1254614142013151 |
oct | 140670044000361 |
9 | 25508574267815 |
10 | 6656135004401 |
11 | 213693a759673 |
12 | 8b600618b495 |
13 | 393894aa432c |
14 | 1902314b6761 |
15 | b821c09e6bb |
hex | 60dc09000f1 |
6656135004401 has 2 divisors, whose sum is σ = 6656135004402. Its totient is φ = 6656135004400.
The previous prime is 6656135004347. The next prime is 6656135004413. The reversal of 6656135004401 is 1044005316566.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3789936794176 + 2866198210225 = 1946776^2 + 1692985^2 .
It is a cyclic number.
It is not a de Polignac number, because 6656135004401 - 214 = 6656134988017 is a prime.
It is not a weakly prime, because it can be changed into another prime (6656135004481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3328067502200 + 3328067502201.
It is an arithmetic number, because the mean of its divisors is an integer number (3328067502201).
Almost surely, 26656135004401 is an apocalyptic number.
It is an amenable number.
6656135004401 is a deficient number, since it is larger than the sum of its proper divisors (1).
6656135004401 is an equidigital number, since it uses as much as digits as its factorization.
6656135004401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 6656135004401 in words is "six trillion, six hundred fifty-six billion, one hundred thirty-five million, four thousand, four hundred one".
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