Base | Representation |
---|---|
bin | 10011011010110100011… |
… | …00011000001100001011 |
3 | 2100210020121211200120211 |
4 | 21231122030120030023 |
5 | 41412443140001011 |
6 | 1230304521301551 |
7 | 66130441662046 |
oct | 11553214301413 |
9 | 2323217750524 |
10 | 667233125131 |
11 | 237a76782621 |
12 | a93930348b7 |
13 | 4abc5aa51a1 |
14 | 24419619c5d |
15 | 125525d8b21 |
hex | 9b5a31830b |
667233125131 has 2 divisors, whose sum is σ = 667233125132. Its totient is φ = 667233125130.
The previous prime is 667233125099. The next prime is 667233125147. The reversal of 667233125131 is 131521332766.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 667233125131 - 25 = 667233125099 is a prime.
It is a super-2 number, since 2×6672331251312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (667233125831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333616562565 + 333616562566.
It is an arithmetic number, because the mean of its divisors is an integer number (333616562566).
Almost surely, 2667233125131 is an apocalyptic number.
667233125131 is a deficient number, since it is larger than the sum of its proper divisors (1).
667233125131 is an equidigital number, since it uses as much as digits as its factorization.
667233125131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 136080, while the sum is 40.
Adding to 667233125131 its reverse (131521332766), we get a palindrome (798754457897).
The spelling of 667233125131 in words is "six hundred sixty-seven billion, two hundred thirty-three million, one hundred twenty-five thousand, one hundred thirty-one".
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