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671531401 is a prime number
BaseRepresentation
bin101000000001101…
…100000110001001
31201210121022220101
4220001230012021
52333403001101
6150345125401
722432631332
oct5001540611
91653538811
10671531401
11315075532
12168a89861
13a9182478
1465287289
153de4c401
hex2806c189

671531401 has 2 divisors, whose sum is σ = 671531402. Its totient is φ = 671531400.

The previous prime is 671531381. The next prime is 671531411. The reversal of 671531401 is 104135176.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 670033225 + 1498176 = 25885^2 + 1224^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-671531401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 671531401.

It is not a weakly prime, because it can be changed into another prime (671531411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335765700 + 335765701.

It is an arithmetic number, because the mean of its divisors is an integer number (335765701).

Almost surely, 2671531401 is an apocalyptic number.

It is an amenable number.

671531401 is a deficient number, since it is larger than the sum of its proper divisors (1).

671531401 is an equidigital number, since it uses as much as digits as its factorization.

671531401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 28.

The square root of 671531401 is about 25913.9229179991. The cubic root of 671531401 is about 875.7001855672.

Adding to 671531401 its reverse (104135176), we get a palindrome (775666577).

The spelling of 671531401 in words is "six hundred seventy-one million, five hundred thirty-one thousand, four hundred one".