Base | Representation |
---|---|
bin | 11110101001101000001110… |
… | …00011011000100100100001 |
3 | 22211122110212101001121102001 |
4 | 33110310013003120210201 |
5 | 32313244312231304323 |
6 | 355203335501124001 |
7 | 20124364415020201 |
oct | 1724640703304441 |
9 | 284573771047361 |
10 | 67401040103713 |
11 | 1a526690aa7098 |
12 | 7686933b59601 |
13 | 2b7bb77154124 |
14 | 1290328d1c401 |
15 | 7bd3c814e3ad |
hex | 3d4d070d8921 |
67401040103713 has 2 divisors, whose sum is σ = 67401040103714. Its totient is φ = 67401040103712.
The previous prime is 67401040103653. The next prime is 67401040103729. The reversal of 67401040103713 is 31730104010476.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66950246029969 + 450794073744 = 8182313^2 + 671412^2 .
It is a cyclic number.
It is not a de Polignac number, because 67401040103713 - 217 = 67401039972641 is a prime.
It is not a weakly prime, because it can be changed into another prime (67401040103513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33700520051856 + 33700520051857.
It is an arithmetic number, because the mean of its divisors is an integer number (33700520051857).
Almost surely, 267401040103713 is an apocalyptic number.
It is an amenable number.
67401040103713 is a deficient number, since it is larger than the sum of its proper divisors (1).
67401040103713 is an equidigital number, since it uses as much as digits as its factorization.
67401040103713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42336, while the sum is 37.
The spelling of 67401040103713 in words is "sixty-seven trillion, four hundred one billion, forty million, one hundred three thousand, seven hundred thirteen".
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