Base | Representation |
---|---|
bin | 110001000011100000110… |
… | …1111001010000100100011 |
3 | 212212112102100011010221111 |
4 | 1202013001233022010203 |
5 | 1340430211314132011 |
6 | 22201131252404151 |
7 | 1264045245612526 |
oct | 142070157120443 |
9 | 25775370133844 |
10 | 6742054052131 |
11 | 216a31a824932 |
12 | 90a7a4316657 |
13 | 39ba082a0248 |
14 | 1944623cabbd |
15 | ba59a015121 |
hex | 621c1bca123 |
6742054052131 has 2 divisors, whose sum is σ = 6742054052132. Its totient is φ = 6742054052130.
The previous prime is 6742054052039. The next prime is 6742054052159. The reversal of 6742054052131 is 1312504502476.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6742054052131 - 217 = 6742053921059 is a prime.
It is a super-2 number, since 2×67420540521312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6742054052731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3371027026065 + 3371027026066.
It is an arithmetic number, because the mean of its divisors is an integer number (3371027026066).
Almost surely, 26742054052131 is an apocalyptic number.
6742054052131 is a deficient number, since it is larger than the sum of its proper divisors (1).
6742054052131 is an equidigital number, since it uses as much as digits as its factorization.
6742054052131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 40.
The spelling of 6742054052131 in words is "six trillion, seven hundred forty-two billion, fifty-four million, fifty-two thousand, one hundred thirty-one".
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