Base | Representation |
---|---|
bin | 11110110000000001011101… |
… | …00000110010101100010011 |
3 | 22212102110222000102221000212 |
4 | 33120000232200302230103 |
5 | 32330344241314101103 |
6 | 355452312553234335 |
7 | 20146303052504066 |
oct | 1730005640625423 |
9 | 285373860387025 |
10 | 67620745456403 |
11 | 1a600884a39437 |
12 | 770142aa029ab |
13 | 2b967bbaa55b9 |
14 | 129ac0c1068dd |
15 | 7c3e8653b7d8 |
hex | 3d802e832b13 |
67620745456403 has 2 divisors, whose sum is σ = 67620745456404. Its totient is φ = 67620745456402.
The previous prime is 67620745456361. The next prime is 67620745456441. The reversal of 67620745456403 is 30465454702676.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 67620745456403 - 214 = 67620745440019 is a prime.
It is a super-3 number, since 3×676207454564033 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (67620745456463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33810372728201 + 33810372728202.
It is an arithmetic number, because the mean of its divisors is an integer number (33810372728202).
Almost surely, 267620745456403 is an apocalyptic number.
67620745456403 is a deficient number, since it is larger than the sum of its proper divisors (1).
67620745456403 is an equidigital number, since it uses as much as digits as its factorization.
67620745456403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 101606400, while the sum is 59.
The spelling of 67620745456403 in words is "sixty-seven trillion, six hundred twenty billion, seven hundred forty-five million, four hundred fifty-six thousand, four hundred three".
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