Base | Representation |
---|---|
bin | 110001010000000011000… |
… | …1011111101101011111111 |
3 | 212222002220022111200120222 |
4 | 1202200012023331223333 |
5 | 1341400323344224142 |
6 | 22221342315131555 |
7 | 1266020304601136 |
oct | 142400613755377 |
9 | 25862808450528 |
10 | 6768972258047 |
11 | 217a7834113aa |
12 | 913a57143bbb |
13 | 3a1408042c3c |
14 | 19589741a91d |
15 | bb1232debd2 |
hex | 628062fdaff |
6768972258047 has 4 divisors (see below), whose sum is σ = 6896688715800. Its totient is φ = 6641255800296.
The previous prime is 6768972258043. The next prime is 6768972258049. The reversal of 6768972258047 is 7408522798676.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6768972258047 - 22 = 6768972258043 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6768972258043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63858228797 + ... + 63858228902.
It is an arithmetic number, because the mean of its divisors is an integer number (1724172178950).
Almost surely, 26768972258047 is an apocalyptic number.
6768972258047 is a deficient number, since it is larger than the sum of its proper divisors (127716457753).
6768972258047 is a wasteful number, since it uses less digits than its factorization.
6768972258047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127716457752.
The product of its (nonzero) digits is 568995840, while the sum is 71.
The spelling of 6768972258047 in words is "six trillion, seven hundred sixty-eight billion, nine hundred seventy-two million, two hundred fifty-eight thousand, forty-seven".
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