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6771340049161 is a prime number
BaseRepresentation
bin110001010001001001101…
…0100010111101100001001
3212222100000022220221101011
41202202103110113230021
51341420201023033121
622222413301123521
71266133055516212
oct142422324275411
925870008827334
106771340049161
112180788a24966
129143b80b95a1
133a16c476237c
14195a3da94409
15bb2111027e1
hex62893517b09

6771340049161 has 2 divisors, whose sum is σ = 6771340049162. Its totient is φ = 6771340049160.

The previous prime is 6771340049143. The next prime is 6771340049167. The reversal of 6771340049161 is 1619400431776.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5033045468025 + 1738294581136 = 2243445^2 + 1318444^2 .

It is a cyclic number.

It is not a de Polignac number, because 6771340049161 - 223 = 6771331660553 is a prime.

It is a super-2 number, since 2×67713400491612 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (6771340049167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3385670024580 + 3385670024581.

It is an arithmetic number, because the mean of its divisors is an integer number (3385670024581).

Almost surely, 26771340049161 is an apocalyptic number.

It is an amenable number.

6771340049161 is a deficient number, since it is larger than the sum of its proper divisors (1).

6771340049161 is an equidigital number, since it uses as much as digits as its factorization.

6771340049161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 762048, while the sum is 49.

The spelling of 6771340049161 in words is "six trillion, seven hundred seventy-one billion, three hundred forty million, forty-nine thousand, one hundred sixty-one".