Base | Representation |
---|---|
bin | 110001010010110110110… |
… | …1110101000110100010111 |
3 | 212222200110200222122001022 |
4 | 1202211231232220310113 |
5 | 1342000202104240101 |
6 | 22224221040151355 |
7 | 1266322631644025 |
oct | 142455556506427 |
9 | 25880420878038 |
10 | 6775004368151 |
11 | 2182299383a68 |
12 | 91505b30855b |
13 | 3a1b59972266 |
14 | 195caa5c7715 |
15 | bb377b6ba1b |
hex | 6296dba8d17 |
6775004368151 has 4 divisors (see below), whose sum is σ = 6775014187032. Its totient is φ = 6774994549272.
The previous prime is 6775004368133. The next prime is 6775004368163. The reversal of 6775004368151 is 1518634005776.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6775004368151 - 210 = 6775004367127 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 6775004368093 and 6775004368102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6775004368351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3789245 + ... + 5282838.
It is an arithmetic number, because the mean of its divisors is an integer number (1693753546758).
Almost surely, 26775004368151 is an apocalyptic number.
6775004368151 is a deficient number, since it is larger than the sum of its proper divisors (9818881).
6775004368151 is an equidigital number, since it uses as much as digits as its factorization.
6775004368151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9818880.
The product of its (nonzero) digits is 4233600, while the sum is 53.
The spelling of 6775004368151 in words is "six trillion, seven hundred seventy-five billion, four million, three hundred sixty-eight thousand, one hundred fifty-one".
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