Base | Representation |
---|---|
bin | 111111001000111000… |
… | …001111001111001001 |
3 | 20110222201200100021211 |
4 | 333020320033033021 |
5 | 2102320420220423 |
6 | 51051111333121 |
7 | 4620005254225 |
oct | 771070171711 |
9 | 213881610254 |
10 | 67794695113 |
11 | 2682a379952 |
12 | 111803811a1 |
13 | 65155a9512 |
14 | 33d1b97785 |
15 | 1b6bbe710d |
hex | fc8e0f3c9 |
67794695113 has 2 divisors, whose sum is σ = 67794695114. Its totient is φ = 67794695112.
The previous prime is 67794695099. The next prime is 67794695117. The reversal of 67794695113 is 31159649776.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67794099129 + 595984 = 260373^2 + 772^2 .
It is a cyclic number.
It is not a de Polignac number, because 67794695113 - 25 = 67794695081 is a prime.
It is a super-2 number, since 2×677946951132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (67794695117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33897347556 + 33897347557.
It is an arithmetic number, because the mean of its divisors is an integer number (33897347557).
Almost surely, 267794695113 is an apocalyptic number.
It is an amenable number.
67794695113 is a deficient number, since it is larger than the sum of its proper divisors (1).
67794695113 is an equidigital number, since it uses as much as digits as its factorization.
67794695113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8573040, while the sum is 58.
The spelling of 67794695113 in words is "sixty-seven billion, seven hundred ninety-four million, six hundred ninety-five thousand, one hundred thirteen".
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